[LeetCode MySQL] 197. Rising Temperature

197. Rising Temperature

Table: Weather

+---------------+---------+
| Column Name   | Type    |
+---------------+---------+
| id            | int     |
| recordDate    | date    |
| temperature   | int     |
+---------------+---------+
id is the primary key for this table.
This table contains information about the temperature in a certain day.

 

Write an SQL query to find all dates' id with higher temperature compared to its previous dates (yesterday).

 

Return the result table in any order.

 

The query result format is in the following example:

Weather
+----+------------+-------------+
| id | recordDate | Temperature |
+----+------------+-------------+
| 1  | 2015-01-01 | 10          |
| 2  | 2015-01-02 | 25          |
| 3  | 2015-01-03 | 20          |
| 4  | 2015-01-04 | 30          |
+----+------------+-------------+

Result table:
+----+
| id |
+----+
| 2  |
| 4  |
+----+
In 2015-01-02, temperature was higher than the previous day (10 -> 25).
In 2015-01-04, temperature was higher than the previous day (20 -> 30).

 

QUERY

select d2.id
from weather d1 inner join weather d2
on adddate(d1.recordDate, interval 1 day) = d2.recordDate
where d2.temperature > d1.temperature

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Reference: 197. Rising Temperature